IRF as % deviation and different steady state
Posted: Fri Jun 16, 2017 7:35 am
Dear all,
I was wondering if someone could explain something to me. If have written my model as a non-linear model; f.e.: y = a*(k_g^alpha)*(k^gamma)*(l^(1-gamma));. As such my impulse responses are in levels. I however, need my impulse responses as % deviations from the steady state. Now I have two questions:
1. I tried to make dynare log-lin my model: exp(y) = exp(a)*(exp(k_g)^alpha)*(exp(k)^gamma)*(exp(l)^(1-gamma)); the impulse responses are then as % deviations from the steady state but the calculated states are very different from my non-linear equation model, with even many negative values. Do I need to convert these values to obtain the level steady state values? Or am I totally missing something?
2. Is there away to type some code in the non-linear equation model that will give me the impulse responses as a % deviation from the steady state? I really prefer this method as I want to continue working with the non-linear equation model.
All tips and tricks are welcome!
I was wondering if someone could explain something to me. If have written my model as a non-linear model; f.e.: y = a*(k_g^alpha)*(k^gamma)*(l^(1-gamma));. As such my impulse responses are in levels. I however, need my impulse responses as % deviations from the steady state. Now I have two questions:
1. I tried to make dynare log-lin my model: exp(y) = exp(a)*(exp(k_g)^alpha)*(exp(k)^gamma)*(exp(l)^(1-gamma)); the impulse responses are then as % deviations from the steady state but the calculated states are very different from my non-linear equation model, with even many negative values. Do I need to convert these values to obtain the level steady state values? Or am I totally missing something?
2. Is there away to type some code in the non-linear equation model that will give me the impulse responses as a % deviation from the steady state? I really prefer this method as I want to continue working with the non-linear equation model.
All tips and tricks are welcome!