Re: How to find steady state normcdf??
Posted: Mon Mar 25, 2013 9:04 amOMG. I cannot find any copy and paste errror. I think i used almost equations in paper.
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STEADY-STATE RESULTS:
C_HD 0.157316
C_MD 0.882245
C_D 1
C_HF 0.0289613
C_MF 0.971335
C_F 1
p_HD 1.41504
p_MD 0.881152
p_D 1
p_HF 1.09932
p_MF 0.996734
p_F 1
mc_D 1.2864
mc_F 0.999384
p_XD 1.76649
p_XF 0.880609
I_D 1
I_HD 0.157316
I_MD 0.882245
I_F 1
I_HF 0.0289613
I_MF 0.971335
K_D 40
K_F 40
Q_D 1
Q_F 1
THETA_D 0.99
THETA_F 0.99
RHO_D 1
RHO_F 1
om_D 0.2837
om_F 0.2837
z_D 0.718022
g_D 0.280505
zph_D -0.96798
gph_D 0.943521
z_F 0.716697
g_F 0.283018
zph_F -0.990222
gph_F 0.983801
i_D 0.010101
i_F 0.010101
r_KD 1.03031
r_KF 1.01511
D_ED 14.2872
D_EF 9.11336
C_ED 0.375811
C_EF 0.0989434
C_EHD 0.059121
C_EMD 0.331558
C_EHF 0.00286553
C_EMF 0.0961071
y_D 4.91391
y_HD 0.383298
y_XD 4.53061
y_F 4.58655
y_HF 0.0611235
y_XF 4.52543
y_MD 2.14958
y_MF 2.05003
w_ED 0.0410882
w_EF 0.0297942
nw_D 29.2567
nw_F 29.0318
w_D 2.54821
w_F 2.05673
n_D 1.58886
n_F 1.42897
h_D 1.59631
h_F 1.43413
D_HD -5.70939
D_HF -1.84305
pi_D 1
pi_F 1
psi_Dt 0
r_D 0.0553111
r_F 0.0401076
PHI_D 0.0200079
PHI_F 0.0049565
s_D 0.801047
s_F 1.24837
Error using print_info (line 36)
The generalized Schur (QZ) decomposition failed. For more
information, see the documentation for Lapack function dgges:
info=43, n=41
Error in check (line 76)
print_info(info, options.noprint);
Error in chay1 (line 517)
oo_.dr.eigval = check(M_,options_,oo_);
Error in dynare (line 120)
evalin('base',fname) ;
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