efi wrote:I would try to get the steady state values as described in this article with dynare. You find a small description in Appendix 1 at the end of the text. You can then use the determined steady state values as initial values.
efi wrote:Hello HouseC,
yes I tried it and I got Steady State Values. But with this initial values, the model does not work...I think I have false timing conventions on my variables. Have you already thought about the selection of predetermined variables?
Here my way to get the steady state values:
First I guess you have to write two .mod-files.
- First you determine the steady state values of the banks. But you have to eliminate the "K" -> then you have the variables DoverK;NioverK and NnoverK. Wenn you run this file you get Z.
- Then use Z as parameter in the second file. You use the second mod.file to determine the remaining variables.
After that you multiply DoverK;NioverK and NnoverK with K to get D, Ni and Nn.
Unfortunately my Lambda_n is negative. I set it to zero...
Then you get the following initial values (Which unfortunatly do not work in the full model):
initval;
%A=0;
PSI=0;
%A_eps=0;
Psi_eps=0;
Qi =1;
Qn = 1.058;
R=1/beta;
Rb=1.0101;
Y = 0.746634;
C =0.574446;
L = 0.249937;
I = 0.172188;
K =6.88751;
Z =0.0357733;
D = 6.2919539;
N_i =0.15078756;
N_n =0.736908;
S_i= 1.85605;
S_n=5.03649;
nu =1.09282;
nu_s =1.1328;
nu_b =1.09282;
lambda_i = 0.449051;
lambda_n =0;
u_C = 1.758216;
Omega = 1.193;
Omega_i = 1.5;
Omega_n = 1.09022104;
efi wrote:Here are my results, but I am not sure how to deal with the value of 'lambda_n':
STEADY-STATE RESULTS:
I 0.172188
C 0.574446
K 6.88753
L 0.249938
Z 0.0357732
Qn 1.058
Nn 0.736906
Ni 0.150788
D 6.29198
nu 1.09283
nu_s 1.1328
nu_b 1.09283
R_b 1.0101
lambda_i 0.449053
lambda_n -0.146422
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