Initial value as arbitrary point

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Initial value as arbitrary point

Postby manof1kvoices » Tue May 08, 2012 10:52 am

Hi all,

I want to investigate the shape of the transition from an arbitrary initial point, different from the steady state, but I still get a jump in the variables as if there was a shock going on. I don't want to shock the system, I just want to see the smooth transition to the ss without any jumps.

For that purpose, I remove the "steady" command after the "initval" block but still get unwanted jumps in the simulation. I quote from the User Guide: "..if you wanted to begin your soulution path from an arbitrary point, you would enter those values in your initival block, followed by the command steady.."

I paste the short code below:

var k Q c m;

varexo pop;

parameters alpha mu beta;
alpha=0.3;
// eta=0.04;
mu=0.8;
beta=0.9;

model;
(pop/c)=beta*((pop/c(+1))*(1+alpha*k^(alpha-1))-pop*mu*alpha*k^(alpha-1)/c(+1));
(1/c)=beta*((1/Q)+(1/c(+1)));
k=k(-1)^(alpha)+k(-1)-c-m;
Q=Q(-1)+pop*(m-mu*k(-1)^(alpha));
end;

initval;
pop=1; // 2 IS THE VALUE FOR POPULATION FOR WHICH Q_RSS IS BELOW THE THRESHOLD AND IT'S STABLE, GIVEN THE PARAMETER VALUES WE ASSIGNED. WE CAN MAKE A NICE GRAPH OUT OF THIS.
k=0.5;
Q=1.4;
c=((1-mu)^(1/(1-alpha)))*((beta/(1-beta))*alpha)^(alpha/(1-alpha));
m=k^(alpha)-c;
end;

// Check that this is indeed the steady state
/* steady;

// Check the Blanchard-Kahn conditions
/* check;

endval;
pop=1;
k=((beta/(1-beta))*(alpha*(1-mu)))^(1/(1-alpha));
c=((1-mu)^(1/(1-alpha)))*((beta/(1-beta))*alpha)^(alpha/(1-alpha));
Q=(beta/(1-beta))*((1-mu)^(1/(1-alpha)))*((beta/(1-beta))*alpha)^(alpha/(1-alpha));
m=k^(alpha)-c;
end;

steady;

check;

simul(periods=100);

rplot c;
rplot k;
rplot Q;
rplot m;

Any help would be much appreciated!!

Thank you
manof1kvoices
 
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